176=-16t^2+196t

Solution for 176=-16t^2+196t equation:

176=-16t^2+196t

We move all terms to the left:

176-(-16t^2+196t)=0

We get rid of parentheses

16t^2-196t+176=0

a = 16; b = -196; c = +176;
Δ = b2-4ac
Δ = -1962-4·16·176
Δ = 27152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27152}=\sqrt{16*1697}=\sqrt{16}*\sqrt{1697}=4\sqrt{1697}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-4\sqrt{1697}}{2*16}=\frac{196-4\sqrt{1697}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+4\sqrt{1697}}{2*16}=\frac{196+4\sqrt{1697}}{32}
$